Base | Representation |
---|---|
bin | 1110110111100101… |
… | …1011010001010001 |
3 | 101022011020201022211 |
4 | 3231321123101101 |
5 | 31133230112342 |
6 | 1500014232121 |
7 | 200623046215 |
oct | 35571332121 |
9 | 11264221284 |
10 | 3991254097 |
11 | 1768a60306 |
12 | 9347b5641 |
13 | 4b7b7b91c |
14 | 29c118945 |
15 | 1855e8c17 |
hex | ede5b451 |
3991254097 has 2 divisors, whose sum is σ = 3991254098. Its totient is φ = 3991254096.
The previous prime is 3991254013. The next prime is 3991254131. The reversal of 3991254097 is 7904521993.
3991254097 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2906935056 + 1084319041 = 53916^2 + 32929^2 .
It is a cyclic number.
It is not a de Polignac number, because 3991254097 - 223 = 3982865489 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3991254097.
It is not a weakly prime, because it can be changed into another prime (3991254697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1995627048 + 1995627049.
It is an arithmetic number, because the mean of its divisors is an integer number (1995627049).
Almost surely, 23991254097 is an apocalyptic number.
It is an amenable number.
3991254097 is a deficient number, since it is larger than the sum of its proper divisors (1).
3991254097 is an equidigital number, since it uses as much as digits as its factorization.
3991254097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 612360, while the sum is 49.
The square root of 3991254097 is about 63176.3729332414. The cubic root of 3991254097 is about 1586.2432697683.
The spelling of 3991254097 in words is "three billion, nine hundred ninety-one million, two hundred fifty-four thousand, ninety-seven".
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