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39912920945 = 57982584189
BaseRepresentation
bin100101001010111111…
…101101011101110001
310211000121012110111022
4211022333231131301
51123220201432240
630200304225225
72612036142002
oct451277553561
9124017173438
1039912920945
1115a21892287
12789a90b215
1339c1013cb1
141d08bc11a9
1510890359b5
hex94afed771

39912920945 has 4 divisors (see below), whose sum is σ = 47895505140. Its totient is φ = 31930336752.

The previous prime is 39912920897. The next prime is 39912920959. The reversal of 39912920945 is 54902921993.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12980500624 + 26932420321 = 113932^2 + 164111^2 .

It is a cyclic number.

It is not a de Polignac number, because 39912920945 - 26 = 39912920881 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3991292090 + ... + 3991292099.

It is an arithmetic number, because the mean of its divisors is an integer number (11973876285).

Almost surely, 239912920945 is an apocalyptic number.

It is an amenable number.

39912920945 is a deficient number, since it is larger than the sum of its proper divisors (7982584195).

39912920945 is an equidigital number, since it uses as much as digits as its factorization.

39912920945 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7982584194.

The product of its (nonzero) digits is 1574640, while the sum is 53.

The spelling of 39912920945 in words is "thirty-nine billion, nine hundred twelve million, nine hundred twenty thousand, nine hundred forty-five".

Divisors: 1 5 7982584189 39912920945