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3993534942497 is a prime number
BaseRepresentation
bin111010000111010001001…
…110110100110100100001
3112010210000022112202021222
4322013101032310310201
51010412224421124442
612254334333224425
7561344342633012
oct72072116646441
915123008482258
103993534942497
1112aa715400241
12545b82932115
1322c786590419
14db406873009
156dd3360c8d2
hex3a1d13b4d21

3993534942497 has 2 divisors, whose sum is σ = 3993534942498. Its totient is φ = 3993534942496.

The previous prime is 3993534942413. The next prime is 3993534942503. The reversal of 3993534942497 is 7942494353993.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3899357153041 + 94177789456 = 1974679^2 + 306884^2 .

It is an emirp because it is prime and its reverse (7942494353993) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3993534942497 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3993534942497.

It is not a weakly prime, because it can be changed into another prime (3993534942697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1996767471248 + 1996767471249.

It is an arithmetic number, because the mean of its divisors is an integer number (1996767471249).

Almost surely, 23993534942497 is an apocalyptic number.

It is an amenable number.

3993534942497 is a deficient number, since it is larger than the sum of its proper divisors (1).

3993534942497 is an equidigital number, since it uses as much as digits as its factorization.

3993534942497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 793618560, while the sum is 71.

The spelling of 3993534942497 in words is "three trillion, nine hundred ninety-three billion, five hundred thirty-four million, nine hundred forty-two thousand, four hundred ninety-seven".