Base | Representation |
---|---|
bin | 111010001001100101010… |
… | …110000010111100100011 |
3 | 112011000102111100210211221 |
4 | 322021211112002330203 |
5 | 1010432322041111311 |
6 | 12255425101515511 |
7 | 561463045256116 |
oct | 72114526027443 |
9 | 15130374323757 |
10 | 3996019863331 |
11 | 1300780045021 |
12 | 546556b72b97 |
13 | 22ca91340192 |
14 | db5a08ba57d |
15 | 6de2b85a671 |
hex | 3a265582f23 |
3996019863331 has 2 divisors, whose sum is σ = 3996019863332. Its totient is φ = 3996019863330.
The previous prime is 3996019863313. The next prime is 3996019863361. The reversal of 3996019863331 is 1333689106993.
Together with previous prime (3996019863313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3996019863331 - 219 = 3996019339043 is a prime.
It is a super-5 number, since 5×39960198633315 (a number of 64 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 3996019863331.
It is not a weakly prime, because it can be changed into another prime (3996019863361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1998009931665 + 1998009931666.
It is an arithmetic number, because the mean of its divisors is an integer number (1998009931666).
Almost surely, 23996019863331 is an apocalyptic number.
3996019863331 is a deficient number, since it is larger than the sum of its proper divisors (1).
3996019863331 is an equidigital number, since it uses as much as digits as its factorization.
3996019863331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17006112, while the sum is 61.
The spelling of 3996019863331 in words is "three trillion, nine hundred ninety-six billion, nineteen million, eight hundred sixty-three thousand, three hundred thirty-one".
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