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3997099814400 = 293252721164373
BaseRepresentation
bin111010001010100101101…
…101101110111000000000
3112011010012202111000012200
4322022211231232320000
51010442030023030100
612300124200553200
7561531600560400
oct72124555567000
915133182430180
103997099814400
111301184706270
125467b8782800
1322cc03cc1394
14db6640ba800
156de91580e00
hex3a2a5b6ee00

3997099814400 has 1080 divisors, whose sum is σ = 18152952750504. Its totient is φ = 830553292800.

The previous prime is 3997099814353. The next prime is 3997099814429. The reversal of 3997099814400 is 44189907993.

3997099814400 is a `hidden beast` number, since 39 + 9 + 70 + 9 + 98 + 1 + 440 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (63).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 107 ways as a sum of consecutive naturals, for example, 62060614 + ... + 62124986.

Almost surely, 23997099814400 is an apocalyptic number.

3997099814400 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3997099814400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (9076476375252).

3997099814400 is an abundant number, since it is smaller than the sum of its proper divisors (14155852936104).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3997099814400 is a wasteful number, since it uses less digits than its factorization.

3997099814400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64432 (or 64401 counting only the distinct ones).

The product of its (nonzero) digits is 17635968, while the sum is 63.

The spelling of 3997099814400 in words is "three trillion, nine hundred ninety-seven billion, ninety-nine million, eight hundred fourteen thousand, four hundred".