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400004121209993 is a prime number
BaseRepresentation
bin101101011110011010011011…
…1100011011010110010001001
31221110022000112222001021102222
41122330310313203122302021
5404412131420012204433
63534423204554503425
7150153226005426656
oct13274646743326211
91843260488037388
10400004121209993
111064a9882378773
1238a4358aa34b75
13142272c42cb051
1470ac434b10c2d
15313a059d47b98
hex16bcd378dac89

400004121209993 has 2 divisors, whose sum is σ = 400004121209994. Its totient is φ = 400004121209992.

The previous prime is 400004121209983. The next prime is 400004121210077. The reversal of 400004121209993 is 399902121400004.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 327262463617609 + 72741657592384 = 18090397^2 + 8528872^2 .

It is a cyclic number.

It is not a de Polignac number, because 400004121209993 - 230 = 400003047468169 is a prime.

It is not a weakly prime, because it can be changed into another prime (400004121209983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200002060604996 + 200002060604997.

It is an arithmetic number, because the mean of its divisors is an integer number (200002060604997).

Almost surely, 2400004121209993 is an apocalyptic number.

It is an amenable number.

400004121209993 is a deficient number, since it is larger than the sum of its proper divisors (1).

400004121209993 is an equidigital number, since it uses as much as digits as its factorization.

400004121209993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 139968, while the sum is 44.

Adding to 400004121209993 its reverse (399902121400004), we get a palindrome (799906242609997).

The spelling of 400004121209993 in words is "four hundred trillion, four billion, one hundred twenty-one million, two hundred nine thousand, nine hundred ninety-three".