Base | Representation |
---|---|
bin | 101101011110100010010010… |
… | …1100111010110011011000011 |
3 | 1221110100122010021200202010011 |
4 | 1122331010211213112123003 |
5 | 404412421002012320003 |
6 | 3534435035512245351 |
7 | 150154364202000103 |
oct | 13275044547263303 |
9 | 1843318107622104 |
10 | 400021000120003 |
11 | 106505a54050679 |
12 | 38a468bb6a0857 |
13 | 14228a841a5372 |
14 | 70ad1966ad203 |
15 | 313a6e6aa146d |
hex | 16bd1259d66c3 |
400021000120003 has 2 divisors, whose sum is σ = 400021000120004. Its totient is φ = 400021000120002.
The previous prime is 400021000119907. The next prime is 400021000120043. The reversal of 400021000120003 is 300021000120004.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 400021000120003 - 221 = 400020998022851 is a prime.
It is not a weakly prime, because it can be changed into another prime (400021000120043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200010500060001 + 200010500060002.
It is an arithmetic number, because the mean of its divisors is an integer number (200010500060002).
Almost surely, 2400021000120003 is an apocalyptic number.
400021000120003 is a deficient number, since it is larger than the sum of its proper divisors (1).
400021000120003 is an equidigital number, since it uses as much as digits as its factorization.
400021000120003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 400021000120003 its reverse (300021000120004), we get a palindrome (700042000240007).
Subtracting from 400021000120003 its reverse (300021000120004), we obtain a palindrome (99999999999999).
The spelling of 400021000120003 in words is "four hundred trillion, twenty-one billion, one hundred twenty thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •