Base | Representation |
---|---|
bin | 10010001100001101111011… |
… | …01110100011001010010001 |
3 | 12020122011201001001200120001 |
4 | 21012012331232203022101 |
5 | 20220344013130232423 |
6 | 221024432503450001 |
7 | 11266031066510551 |
oct | 1106067556431221 |
9 | 166564631050501 |
10 | 40002213524113 |
11 | 11822930751545 |
12 | 45a0844456901 |
13 | 1942267052a49 |
14 | 9c4190477161 |
15 | 49583920acad |
hex | 2461bdba3291 |
40002213524113 has 2 divisors, whose sum is σ = 40002213524114. Its totient is φ = 40002213524112.
The previous prime is 40002213524033. The next prime is 40002213524123. The reversal of 40002213524113 is 31142531220004.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31368154129984 + 8634059394129 = 5600728^2 + 2938377^2 .
It is a cyclic number.
It is not a de Polignac number, because 40002213524113 - 225 = 40002179969681 is a prime.
It is not a weakly prime, because it can be changed into another prime (40002213524123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20001106762056 + 20001106762057.
It is an arithmetic number, because the mean of its divisors is an integer number (20001106762057).
Almost surely, 240002213524113 is an apocalyptic number.
It is an amenable number.
40002213524113 is a deficient number, since it is larger than the sum of its proper divisors (1).
40002213524113 is an equidigital number, since it uses as much as digits as its factorization.
40002213524113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 40002213524113 its reverse (31142531220004), we get a palindrome (71144744744117).
The spelling of 40002213524113 in words is "forty trillion, two billion, two hundred thirteen million, five hundred twenty-four thousand, one hundred thirteen".
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