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40002213524113 is a prime number
BaseRepresentation
bin10010001100001101111011…
…01110100011001010010001
312020122011201001001200120001
421012012331232203022101
520220344013130232423
6221024432503450001
711266031066510551
oct1106067556431221
9166564631050501
1040002213524113
1111822930751545
1245a0844456901
131942267052a49
149c4190477161
1549583920acad
hex2461bdba3291

40002213524113 has 2 divisors, whose sum is σ = 40002213524114. Its totient is φ = 40002213524112.

The previous prime is 40002213524033. The next prime is 40002213524123. The reversal of 40002213524113 is 31142531220004.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31368154129984 + 8634059394129 = 5600728^2 + 2938377^2 .

It is a cyclic number.

It is not a de Polignac number, because 40002213524113 - 225 = 40002179969681 is a prime.

It is not a weakly prime, because it can be changed into another prime (40002213524123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20001106762056 + 20001106762057.

It is an arithmetic number, because the mean of its divisors is an integer number (20001106762057).

Almost surely, 240002213524113 is an apocalyptic number.

It is an amenable number.

40002213524113 is a deficient number, since it is larger than the sum of its proper divisors (1).

40002213524113 is an equidigital number, since it uses as much as digits as its factorization.

40002213524113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 40002213524113 its reverse (31142531220004), we get a palindrome (71144744744117).

The spelling of 40002213524113 in words is "forty trillion, two billion, two hundred thirteen million, five hundred twenty-four thousand, one hundred thirteen".