4000400113 has 2 divisors, whose sum is σ = 4000400114. Its totient is φ = 4000400112.

The previous prime is 4000400093. The next prime is 4000400149. The reversal of 4000400113 is 3110040004.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3632834529 + 367565584 = 60273^2 + 19172^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4000400113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4000400093 and 4000400102.

It is not a weakly prime, because it can be changed into another prime (4000407113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2000200056 + 2000200057.

It is an arithmetic number, because the mean of its divisors is an integer number (2000200057).

Almost surely, 2^4000400113 is an apocalyptic number.

It is an amenable number.

4000400113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4000400113 is an equidigital number, since it uses as much as digits as its factorization.

4000400113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 4000400113 is about 63248.7162952735. The cubic root of 4000400113 is about 1587.4539785199.

Adding to 4000400113 its reverse (3110040004), we get a palindrome (7110440117).

The spelling of 4000400113 in words is "four billion, four hundred thousand, one hundred thirteen".