Base | Representation |
---|---|
bin | 1011101001001000100… |
… | …01000010010001010011 |
3 | 1102020120111121002221011 |
4 | 11310210101002101103 |
5 | 23023240320412201 |
6 | 503435342111351 |
7 | 40621242221041 |
oct | 5644421022123 |
9 | 1366514532834 |
10 | 400040404051 |
11 | 144724419582 |
12 | 6564487b557 |
13 | 2b953b16a72 |
14 | 1550d6bd391 |
15 | a61522a151 |
hex | 5d24442453 |
400040404051 has 2 divisors, whose sum is σ = 400040404052. Its totient is φ = 400040404050.
The previous prime is 400040404031. The next prime is 400040404063. The reversal of 400040404051 is 150404040004.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 400040404051 - 223 = 400032015443 is a prime.
It is not a weakly prime, because it can be changed into another prime (400040404021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200020202025 + 200020202026.
It is an arithmetic number, because the mean of its divisors is an integer number (200020202026).
Almost surely, 2400040404051 is an apocalyptic number.
400040404051 is a deficient number, since it is larger than the sum of its proper divisors (1).
400040404051 is an equidigital number, since it uses as much as digits as its factorization.
400040404051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1280, while the sum is 22.
Adding to 400040404051 its reverse (150404040004), we get a palindrome (550444444055).
The spelling of 400040404051 in words is "four hundred billion, forty million, four hundred four thousand, fifty-one".
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