Base | Representation |
---|---|
bin | 101101011110110010010010… |
… | …1000110000001010011101011 |
3 | 1221110110220210021011101222012 |
4 | 1122331210211012001103223 |
5 | 404414001324341334011 |
6 | 3534502520253350135 |
7 | 150160021353456326 |
oct | 13275444506012353 |
9 | 1843426707141865 |
10 | 400055351121131 |
11 | 106519581317202 |
12 | 38a514a779834b |
13 | 1422c099b05934 |
14 | 70b0ad49197bd |
15 | 313b557685a8b |
hex | 16bd9251814eb |
400055351121131 has 16 divisors (see below), whose sum is σ = 421522308547200. Its totient is φ = 378629715644928.
The previous prime is 400055351121121. The next prime is 400055351121133. The reversal of 400055351121131 is 131121153550004.
It is a cyclic number.
It is not a de Polignac number, because 400055351121131 - 210 = 400055351120107 is a prime.
It is a super-2 number, since 2×4000553511211312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (400055351121133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 77264600 + ... + 82279578.
It is an arithmetic number, because the mean of its divisors is an integer number (26345144284200).
Almost surely, 2400055351121131 is an apocalyptic number.
400055351121131 is a deficient number, since it is larger than the sum of its proper divisors (21466957426069).
400055351121131 is a wasteful number, since it uses less digits than its factorization.
400055351121131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5019098.
The product of its (nonzero) digits is 9000, while the sum is 32.
The spelling of 400055351121131 in words is "four hundred trillion, fifty-five billion, three hundred fifty-one million, one hundred twenty-one thousand, one hundred thirty-one".
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