Base | Representation |
---|---|
bin | 10010001100011010011111… |
… | …00001001011010100001011 |
3 | 12020122211002211022200101001 |
4 | 21012031033201023110023 |
5 | 20221001314320200103 |
6 | 221031505425235431 |
7 | 11266360121512246 |
oct | 1106151741132413 |
9 | 166584084280331 |
10 | 40008954459403 |
11 | 1182577a840a46 |
12 | 45a2005a92b77 |
13 | 1942a9c791357 |
14 | 9c462d83825d |
15 | 495ad0e0001d |
hex | 24634f84b50b |
40008954459403 has 2 divisors, whose sum is σ = 40008954459404. Its totient is φ = 40008954459402.
The previous prime is 40008954459379. The next prime is 40008954459413. The reversal of 40008954459403 is 30495445980004.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40008954459403 - 213 = 40008954451211 is a prime.
It is not a weakly prime, because it can be changed into another prime (40008954459413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20004477229701 + 20004477229702.
It is an arithmetic number, because the mean of its divisors is an integer number (20004477229702).
Almost surely, 240008954459403 is an apocalyptic number.
40008954459403 is a deficient number, since it is larger than the sum of its proper divisors (1).
40008954459403 is an equidigital number, since it uses as much as digits as its factorization.
40008954459403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12441600, while the sum is 55.
The spelling of 40008954459403 in words is "forty trillion, eight billion, nine hundred fifty-four million, four hundred fifty-nine thousand, four hundred three".
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