Base | Representation |
---|---|
bin | 111010001110100000000… |
… | …100101001010101001001 |
3 | 112011112001111002220010222 |
4 | 322032200010221111021 |
5 | 1011024130313000001 |
6 | 12302101044115425 |
7 | 562040642614034 |
oct | 72164004512511 |
9 | 15145044086128 |
10 | 4001300125001 |
11 | 1302a3a674843 |
12 | 54758b395b75 |
13 | 23042327857a |
14 | db941c9401b |
15 | 6e13a1c261b |
hex | 3a3a0129549 |
4001300125001 has 2 divisors, whose sum is σ = 4001300125002. Its totient is φ = 4001300125000.
The previous prime is 4001300124971. The next prime is 4001300125007. The reversal of 4001300125001 is 1005210031004.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4001296104976 + 4020025 = 2000324^2 + 2005^2 .
It is a cyclic number.
It is not a de Polignac number, because 4001300125001 - 26 = 4001300124937 is a prime.
It is not a weakly prime, because it can be changed into another prime (4001300125007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2000650062500 + 2000650062501.
It is an arithmetic number, because the mean of its divisors is an integer number (2000650062501).
Almost surely, 24001300125001 is an apocalyptic number.
It is an amenable number.
4001300125001 is a deficient number, since it is larger than the sum of its proper divisors (1).
4001300125001 is an equidigital number, since it uses as much as digits as its factorization.
4001300125001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 17.
Adding to 4001300125001 its reverse (1005210031004), we get a palindrome (5006510156005).
The spelling of 4001300125001 in words is "four trillion, one billion, three hundred million, one hundred twenty-five thousand, one".
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