Base | Representation |
---|---|
bin | 10010001100100010011101… |
… | …00100001101000100110001 |
3 | 12020200020011000222120112111 |
4 | 21012101032210031010301 |
5 | 20221034100230134441 |
6 | 221033454202525321 |
7 | 11266601140334401 |
oct | 1106211644150461 |
9 | 166606130876474 |
10 | 40013233443121 |
11 | 11827576154824 |
12 | 45a29bab06841 |
13 | 1943302132993 |
14 | 9c4917c50801 |
15 | 495c818d2081 |
hex | 24644e90d131 |
40013233443121 has 2 divisors, whose sum is σ = 40013233443122. Its totient is φ = 40013233443120.
The previous prime is 40013233443097. The next prime is 40013233443173. The reversal of 40013233443121 is 12134433231004.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33925965160000 + 6087268283121 = 5824600^2 + 2467239^2 .
It is a cyclic number.
It is not a de Polignac number, because 40013233443121 - 213 = 40013233434929 is a prime.
It is not a weakly prime, because it can be changed into another prime (40013233441121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20006616721560 + 20006616721561.
It is an arithmetic number, because the mean of its divisors is an integer number (20006616721561).
Almost surely, 240013233443121 is an apocalyptic number.
It is an amenable number.
40013233443121 is a deficient number, since it is larger than the sum of its proper divisors (1).
40013233443121 is an equidigital number, since it uses as much as digits as its factorization.
40013233443121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 40013233443121 its reverse (12134433231004), we get a palindrome (52147666674125).
The spelling of 40013233443121 in words is "forty trillion, thirteen billion, two hundred thirty-three million, four hundred forty-three thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •