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400143132023113 is a prime number
BaseRepresentation
bin101101011111011011001010…
…1001111100101100101001001
31221110210022100212102020220001
41122332312111033211211021
5404421421113244214423
63535011114523003001
7150166246556022343
oct13276662517454511
91843708325366801
10400143132023113
11106552827354096
1238a66505369461
1314237448c6a85b
1470b5060c08293
15313d993cc1cad
hex16bed953e5949

400143132023113 has 2 divisors, whose sum is σ = 400143132023114. Its totient is φ = 400143132023112.

The previous prime is 400143132023083. The next prime is 400143132023161. The reversal of 400143132023113 is 311320231341004.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 394516999452304 + 5626132570809 = 19862452^2 + 2371947^2 .

It is a cyclic number.

It is not a de Polignac number, because 400143132023113 - 237 = 400005693069641 is a prime.

It is a super-2 number, since 2×4001431320231132 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (400143132003113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200071566011556 + 200071566011557.

It is an arithmetic number, because the mean of its divisors is an integer number (200071566011557).

Almost surely, 2400143132023113 is an apocalyptic number.

It is an amenable number.

400143132023113 is a deficient number, since it is larger than the sum of its proper divisors (1).

400143132023113 is an equidigital number, since it uses as much as digits as its factorization.

400143132023113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 400143132023113 its reverse (311320231341004), we get a palindrome (711463363364117).

The spelling of 400143132023113 in words is "four hundred trillion, one hundred forty-three billion, one hundred thirty-two million, twenty-three thousand, one hundred thirteen".