Base | Representation |
---|---|
bin | 111010010001000001110… |
… | …101010101101001011011 |
3 | 112011210001121210002212102 |
4 | 322101001311111221123 |
5 | 1011100210042134321 |
6 | 12303230232234015 |
7 | 562165125424631 |
oct | 72210165255133 |
9 | 15153047702772 |
10 | 4004014021211 |
11 | 1304102592176 |
12 | 54800823b90b |
13 | 2307665b9109 |
14 | dbb1c4a3351 |
15 | 6e24859ec0b |
hex | 3a441d55a5b |
4004014021211 has 2 divisors, whose sum is σ = 4004014021212. Its totient is φ = 4004014021210.
The previous prime is 4004014021187. The next prime is 4004014021223. The reversal of 4004014021211 is 1121204104004.
4004014021211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4004014021211 - 214 = 4004014004827 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (4004014081211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2002007010605 + 2002007010606.
It is an arithmetic number, because the mean of its divisors is an integer number (2002007010606).
Almost surely, 24004014021211 is an apocalyptic number.
4004014021211 is a deficient number, since it is larger than the sum of its proper divisors (1).
4004014021211 is an equidigital number, since it uses as much as digits as its factorization.
4004014021211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 256, while the sum is 20.
Adding to 4004014021211 its reverse (1121204104004), we get a palindrome (5125218125215).
The spelling of 4004014021211 in words is "four trillion, four billion, fourteen million, twenty-one thousand, two hundred eleven".
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