40041211214003 has 2 divisors, whose sum is σ = 40041211214004. Its totient is φ = 40041211214002.

The previous prime is 40041211213987. The next prime is 40041211214029. The reversal of 40041211214003 is 30041211214004.

40041211214003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 40041211214003 - 2⁴ = 40041211213987 is a prime.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 40041211214003.

It is not a weakly prime, because it can be changed into another prime (40041211214033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20020605607001 + 20020605607002.

It is an arithmetic number, because the mean of its divisors is an integer number (20020605607002).

Almost surely, 2^{40041211214003} is an apocalyptic number.

40041211214003 is a deficient number, since it is larger than the sum of its proper divisors (1).

40041211214003 is an equidigital number, since it uses as much as digits as its factorization.

40041211214003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 40041211214003 its reverse (30041211214004), we get a palindrome (70082422428007).

Subtracting from 40041211214003 its reverse (30041211214004), we obtain a palindrome (9999999999999).

The spelling of 40041211214003 in words is "forty trillion, forty-one billion, two hundred eleven million, two hundred fourteen thousand, three".