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4004220022051 is a prime number
BaseRepresentation
bin111010010001001110000…
…111001010110100100011
3112011210120222102000220011
4322101032013022310203
51011101120311201201
612303302511425351
7562203206414314
oct72211607126443
915153528360804
104004220022051
1113041a88a36a7
12548065225257
1323079a1948c2
14dbb3b9a860b
156e25b6e2151
hex3a44e1cad23

4004220022051 has 2 divisors, whose sum is σ = 4004220022052. Its totient is φ = 4004220022050.

The previous prime is 4004220022001. The next prime is 4004220022111. The reversal of 4004220022051 is 1502200224004.

4004220022051 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4004220022051 - 231 = 4002072538403 is a prime.

It is a super-2 number, since 2×40042200220512 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4004220022001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2002110011025 + 2002110011026.

It is an arithmetic number, because the mean of its divisors is an integer number (2002110011026).

Almost surely, 24004220022051 is an apocalyptic number.

4004220022051 is a deficient number, since it is larger than the sum of its proper divisors (1).

4004220022051 is an equidigital number, since it uses as much as digits as its factorization.

4004220022051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1280, while the sum is 22.

Adding to 4004220022051 its reverse (1502200224004), we get a palindrome (5506420246055).

The spelling of 4004220022051 in words is "four trillion, four billion, two hundred twenty million, twenty-two thousand, fifty-one".