Base | Representation |
---|---|
bin | 101101100010000110011111… |
… | …0010001100011111001011011 |
3 | 1221112002111000000101112102122 |
4 | 1123010030332101203321123 |
5 | 404443433102232011141 |
6 | 3535452122022051455 |
7 | 150234652640122064 |
oct | 13304147621437133 |
9 | 1845074000345378 |
10 | 400511040110171 |
11 | 106684861928291 |
12 | 38b05880b79b8b |
13 | 1426304b9c7ba3 |
14 | 70c8ba2bbd56b |
15 | 31483280c564b |
hex | 16c433e463e5b |
400511040110171 has 2 divisors, whose sum is σ = 400511040110172. Its totient is φ = 400511040110170.
The previous prime is 400511040110039. The next prime is 400511040110191. The reversal of 400511040110171 is 171011040115004.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-400511040110171 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 400511040110171.
It is not a weakly prime, because it can be changed into another prime (400511040110191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200255520055085 + 200255520055086.
It is an arithmetic number, because the mean of its divisors is an integer number (200255520055086).
Almost surely, 2400511040110171 is an apocalyptic number.
400511040110171 is a deficient number, since it is larger than the sum of its proper divisors (1).
400511040110171 is an equidigital number, since it uses as much as digits as its factorization.
400511040110171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 560, while the sum is 26.
Adding to 400511040110171 its reverse (171011040115004), we get a palindrome (571522080225175).
The spelling of 400511040110171 in words is "four hundred trillion, five hundred eleven billion, forty million, one hundred ten thousand, one hundred seventy-one".
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