Base | Representation |
---|---|
bin | 10010001110010011101101… |
… | …11110101010101111100011 |
3 | 12020220001002211011002101111 |
4 | 21013021312332222233203 |
5 | 20223033113444324141 |
6 | 221121432120044151 |
7 | 11304153044206036 |
oct | 1107116676525743 |
9 | 166801084132344 |
10 | 40074041011171 |
11 | 1185033a4716a2 |
12 | 45b274b303657 |
13 | 1948c72c9268b |
14 | 9c7845a7d01d |
15 | 49763eea4381 |
hex | 247276faabe3 |
40074041011171 has 2 divisors, whose sum is σ = 40074041011172. Its totient is φ = 40074041011170.
The previous prime is 40074041011033. The next prime is 40074041011181. The reversal of 40074041011171 is 17111014047004.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40074041011171 is a prime.
It is not a weakly prime, because it can be changed into another prime (40074041011181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20037020505585 + 20037020505586.
It is an arithmetic number, because the mean of its divisors is an integer number (20037020505586).
Almost surely, 240074041011171 is an apocalyptic number.
40074041011171 is a deficient number, since it is larger than the sum of its proper divisors (1).
40074041011171 is an equidigital number, since it uses as much as digits as its factorization.
40074041011171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3136, while the sum is 31.
Adding to 40074041011171 its reverse (17111014047004), we get a palindrome (57185055058175).
The spelling of 40074041011171 in words is "forty trillion, seventy-four billion, forty-one million, eleven thousand, one hundred seventy-one".
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