Base | Representation |
---|---|
bin | 10010001111001110010101… |
… | …01110100110100010000001 |
3 | 12021000001100000012212221211 |
4 | 21013213022232212202001 |
5 | 20224042041234404313 |
6 | 221144114540050121 |
7 | 11306345642402152 |
oct | 1107471256464201 |
9 | 167001300185854 |
10 | 40105510856833 |
11 | 1186271936a504 |
12 | 45b8872533941 |
13 | 194bc19a1c726 |
14 | 9c918d3bb929 |
15 | 498382b6ce3d |
hex | 2479caba6881 |
40105510856833 has 2 divisors, whose sum is σ = 40105510856834. Its totient is φ = 40105510856832.
The previous prime is 40105510856821. The next prime is 40105510856911. The reversal of 40105510856833 is 33865801550104.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33391027579009 + 6714483277824 = 5778497^2 + 2591232^2 .
It is a cyclic number.
It is not a de Polignac number, because 40105510856833 - 233 = 40096920922241 is a prime.
It is not a weakly prime, because it can be changed into another prime (40105510853833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20052755428416 + 20052755428417.
It is an arithmetic number, because the mean of its divisors is an integer number (20052755428417).
Almost surely, 240105510856833 is an apocalyptic number.
It is an amenable number.
40105510856833 is a deficient number, since it is larger than the sum of its proper divisors (1).
40105510856833 is an equidigital number, since it uses as much as digits as its factorization.
40105510856833 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728000, while the sum is 49.
The spelling of 40105510856833 in words is "forty trillion, one hundred five billion, five hundred ten million, eight hundred fifty-six thousand, eight hundred thirty-three".
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