4011102013 has 4 divisors (see below), whose sum is σ = 4017170908. Its totient is φ = 4005033120.

The previous prime is 4011101993. The next prime is 4011102041. The reversal of 4011102013 is 3102011104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3194171289 + 816930724 = 56517^2 + 28582^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4011102013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4011101984 and 4011102002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4011102083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3033456 + ... + 3034777.

It is an arithmetic number, because the mean of its divisors is an integer number (1004292727).

Almost surely, 2^4011102013 is an apocalyptic number.

It is an amenable number.

4011102013 is a deficient number, since it is larger than the sum of its proper divisors (6068895).

4011102013 is an equidigital number, since it uses as much as digits as its factorization.

4011102013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6068894.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 4011102013 is about 63333.2615060996. The cubic root of 4011102013 is about 1588.8683076063.

Adding to 4011102013 its reverse (3102011104), we get a palindrome (7113113117).

Subtracting from 4011102013 its reverse (3102011104), we obtain a palindrome (909090909).

The spelling of 4011102013 in words is "four billion, eleven million, one hundred two thousand, thirteen".