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401121202313542 = 2590394133970631
BaseRepresentation
bin101101100110100010100111…
…0110001101001100101000110
31221121020210221021020000020111
41123031011032301221211012
5410033432210243013132
63541040311511423234
7150330023220226144
oct13315051661514506
91847223837200214
10401121202313542
1110689a601552667
1238ba3b87084b1a
13142a874ab25189
14710a52696a594
15315913a191647
hex16cd14ec69946

401121202313542 has 8 divisors (see below), whose sum is σ = 601681923094032. Its totient is φ = 200560561282200.

The previous prime is 401121202313539. The next prime is 401121202313603. The reversal of 401121202313542 is 245313202121104.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×4011212023135422 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5177434 + ... + 28793197.

It is an arithmetic number, because the mean of its divisors is an integer number (75210240386754).

Almost surely, 2401121202313542 is an apocalyptic number.

401121202313542 is a deficient number, since it is larger than the sum of its proper divisors (200560720780490).

401121202313542 is a wasteful number, since it uses less digits than its factorization.

401121202313542 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39874574.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 401121202313542 its reverse (245313202121104), we get a palindrome (646434404434646).

The spelling of 401121202313542 in words is "four hundred one trillion, one hundred twenty-one billion, two hundred two million, three hundred thirteen thousand, five hundred forty-two".

Divisors: 1 2 5903941 11807882 33970631 67941262 200560601156771 401121202313542