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40113254014112 = 251253539187941
BaseRepresentation
bin10010001111011100110000…
…10000011001110010100000
312021000210022122100000212202
421013232120100121302200
520224203421011422422
6221151435142512332
711310041554220546
oct1107563020316240
9167023278300782
1040113254014112
1111865a32160144
1245ba2737356a8
13194c881c956b6
149c96c5907d96
15498687831b92
hex247b98419ca0

40113254014112 has 12 divisors (see below), whose sum is σ = 78972968840346. Its totient is φ = 20056627007040.

The previous prime is 40113254014091. The next prime is 40113254014129. The reversal of 40113254014112 is 21141045231104.

It can be written as a sum of positive squares in only one way, i.e., 34458731464336 + 5654522549776 = 5870156^2 + 2377924^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626769593939 + ... + 626769594002.

Almost surely, 240113254014112 is an apocalyptic number.

It is an amenable number.

40113254014112 is a deficient number, since it is larger than the sum of its proper divisors (38859714826234).

40113254014112 is a wasteful number, since it uses less digits than its factorization.

40113254014112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1253539187951 (or 1253539187943 counting only the distinct ones).

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 40113254014112 its reverse (21141045231104), we get a palindrome (61254299245216).

The spelling of 40113254014112 in words is "forty trillion, one hundred thirteen billion, two hundred fifty-four million, fourteen thousand, one hundred twelve".

Divisors: 1 2 4 8 16 32 1253539187941 2507078375882 5014156751764 10028313503528 20056627007056 40113254014112