Base | Representation |
---|---|
bin | 10010001111011101010001… |
… | …10101010101100001001100 |
3 | 12021000211001000122212002012 |
4 | 21013232220311111201030 |
5 | 20224210003211201104 |
6 | 221151522515520352 |
7 | 11310051502200254 |
oct | 1107565065254114 |
9 | 167024030585065 |
10 | 40113532131404 |
11 | 11866065148846 |
12 | 45ba3308b90b8 |
13 | 194c8c77a1144 |
14 | 9c9710822964 |
15 | 4986a1e6bd6e |
hex | 247ba8d5584c |
40113532131404 has 6 divisors (see below), whose sum is σ = 70198681229964. Its totient is φ = 20056766065700.
The previous prime is 40113532131403. The next prime is 40113532131493. The reversal of 40113532131404 is 40413123531104.
It is a super-2 number, since 2×401135321314042 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (40113532131403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5014191516422 + ... + 5014191516429.
It is an arithmetic number, because the mean of its divisors is an integer number (11699780204994).
Almost surely, 240113532131404 is an apocalyptic number.
It is an amenable number.
40113532131404 is a deficient number, since it is larger than the sum of its proper divisors (30085149098560).
40113532131404 is a wasteful number, since it uses less digits than its factorization.
40113532131404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10028383032855 (or 10028383032853 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 40113532131404 its reverse (40413123531104), we get a palindrome (80526655662508).
The spelling of 40113532131404 in words is "forty trillion, one hundred thirteen billion, five hundred thirty-two million, one hundred thirty-one thousand, four hundred four".
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