Base | Representation |
---|---|
bin | 111010010111111010010… |
… | …000011111011010101001 |
3 | 112012111010120122220211101 |
4 | 322113322100133122221 |
5 | 1011210323144123103 |
6 | 12310451350201401 |
7 | 562546210610641 |
oct | 72277220373251 |
9 | 15174116586741 |
10 | 4011403114153 |
11 | 1307254532056 |
12 | 54952a953261 |
13 | 2313733b4c66 |
14 | dc21d985521 |
15 | 6e52c125a1d |
hex | 3a5fa41f6a9 |
4011403114153 has 2 divisors, whose sum is σ = 4011403114154. Its totient is φ = 4011403114152.
The previous prime is 4011403114123. The next prime is 4011403114283. The reversal of 4011403114153 is 3514113041104.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3350902319209 + 660500794944 = 1830547^2 + 812712^2 .
It is a cyclic number.
It is not a de Polignac number, because 4011403114153 - 225 = 4011369559721 is a prime.
It is not a weakly prime, because it can be changed into another prime (4011403114123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005701557076 + 2005701557077.
It is an arithmetic number, because the mean of its divisors is an integer number (2005701557077).
Almost surely, 24011403114153 is an apocalyptic number.
It is an amenable number.
4011403114153 is a deficient number, since it is larger than the sum of its proper divisors (1).
4011403114153 is an equidigital number, since it uses as much as digits as its factorization.
4011403114153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 4011403114153 its reverse (3514113041104), we get a palindrome (7525516155257).
The spelling of 4011403114153 in words is "four trillion, eleven billion, four hundred three million, one hundred fourteen thousand, one hundred fifty-three".
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