Base | Representation |
---|---|
bin | 111010010111111010010… |
… | …000111011111111111111 |
3 | 112012111010120212212102121 |
4 | 322113322100323333333 |
5 | 1011210323211344411 |
6 | 12310451352503411 |
7 | 562546211606164 |
oct | 72277220737777 |
9 | 15174116785377 |
10 | 4011403231231 |
11 | 1307254602010 |
12 | 54952a9aab67 |
13 | 231373426336 |
14 | dc21d9b606b |
15 | 6e52c14a571 |
hex | 3a5fa43bfff |
4011403231231 has 16 divisors (see below), whose sum is σ = 4396876323840. Its totient is φ = 3629405574720.
The previous prime is 4011403231229. The next prime is 4011403231261. The reversal of 4011403231231 is 1321323041104.
It is a cyclic number.
It is not a de Polignac number, because 4011403231231 - 21 = 4011403231229 is a prime.
It is a super-2 number, since 2×40114032312312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4011403231196 and 4011403231205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4011403231261) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9028416 + ... + 9462298.
It is an arithmetic number, because the mean of its divisors is an integer number (274804770240).
Almost surely, 24011403231231 is an apocalyptic number.
4011403231231 is a deficient number, since it is larger than the sum of its proper divisors (385473092609).
4011403231231 is a wasteful number, since it uses less digits than its factorization.
4011403231231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437886.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 4011403231231 its reverse (1321323041104), we get a palindrome (5332726272335).
The spelling of 4011403231231 in words is "four trillion, eleven billion, four hundred three million, two hundred thirty-one thousand, two hundred thirty-one".
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