Base | Representation |
---|---|
bin | 101101100110110000101100… |
… | …0100111111100101001101011 |
3 | 1221121100200222001022010011202 |
4 | 1123031201120213330221223 |
5 | 410034431113133012301 |
6 | 3541102231321314415 |
7 | 150332143312050521 |
oct | 13315413047745153 |
9 | 1847320861263152 |
10 | 401151432313451 |
11 | 1069014045a9a66 |
12 | 38ba9a03035a0b |
13 | 142ab557a494a1 |
14 | 710bb93766311 |
15 | 3159d0909d66b |
hex | 16cd8589fca6b |
401151432313451 has 16 divisors (see below), whose sum is σ = 419259963876864. Its totient is φ = 383443787278944.
The previous prime is 401151432313421. The next prime is 401151432313453. The reversal of 401151432313451 is 154313234151104.
It is a cyclic number.
It is not a de Polignac number, because 401151432313451 - 222 = 401151428119147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (401151432313453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7668056 + ... + 29344538.
It is an arithmetic number, because the mean of its divisors is an integer number (26203747742304).
Almost surely, 2401151432313451 is an apocalyptic number.
401151432313451 is a deficient number, since it is larger than the sum of its proper divisors (18108531563413).
401151432313451 is a wasteful number, since it uses less digits than its factorization.
401151432313451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21685730.
The product of its (nonzero) digits is 86400, while the sum is 38.
Adding to 401151432313451 its reverse (154313234151104), we get a palindrome (555464666464555).
The spelling of 401151432313451 in words is "four hundred one trillion, one hundred fifty-one billion, four hundred thirty-two million, three hundred thirteen thousand, four hundred fifty-one".
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