Base | Representation |
---|---|
bin | 1011101011001111011… |
… | …11110001100100000001 |
3 | 1102100111101220100101112 |
4 | 11311213233301210001 |
5 | 23033100132114203 |
6 | 504143543413105 |
7 | 40661300201006 |
oct | 5654757614401 |
9 | 1370441810345 |
10 | 401172535553 |
11 | 14515548a749 |
12 | 658bba54195 |
13 | 2baa453796a |
14 | 155b9bc38ad |
15 | a67e80b6d8 |
hex | 5d67bf1901 |
401172535553 has 2 divisors, whose sum is σ = 401172535554. Its totient is φ = 401172535552.
The previous prime is 401172535469. The next prime is 401172535567. The reversal of 401172535553 is 355535271104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 399287499664 + 1885035889 = 631892^2 + 43417^2 .
It is a cyclic number.
It is not a de Polignac number, because 401172535553 - 214 = 401172519169 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 401172535553.
It is not a weakly prime, because it can be changed into another prime (401172535573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200586267776 + 200586267777.
It is an arithmetic number, because the mean of its divisors is an integer number (200586267777).
Almost surely, 2401172535553 is an apocalyptic number.
It is an amenable number.
401172535553 is a deficient number, since it is larger than the sum of its proper divisors (1).
401172535553 is an equidigital number, since it uses as much as digits as its factorization.
401172535553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 315000, while the sum is 41.
The spelling of 401172535553 in words is "four hundred one billion, one hundred seventy-two million, five hundred thirty-five thousand, five hundred fifty-three".
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