Base | Representation |
---|---|
bin | 10010001111101011000100… |
… | …10101101110100101000001 |
3 | 12021001112011020200210221101 |
4 | 21013311202111232211001 |
5 | 20224320140434444123 |
6 | 221155145522454401 |
7 | 11310433164550345 |
oct | 1107654225564501 |
9 | 167045136623841 |
10 | 40120939374913 |
11 | 118692163654a1 |
12 | 45bb859504401 |
13 | 1950508283677 |
14 | 9c9c144ab625 |
15 | 4989873caaad |
hex | 247d6256e941 |
40120939374913 has 2 divisors, whose sum is σ = 40120939374914. Its totient is φ = 40120939374912.
The previous prime is 40120939374851. The next prime is 40120939374973. The reversal of 40120939374913 is 31947393902104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 40110790222864 + 10149152049 = 6333308^2 + 100743^2 .
It is a cyclic number.
It is not a de Polignac number, because 40120939374913 - 213 = 40120939366721 is a prime.
It is not a weakly prime, because it can be changed into another prime (40120939374973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20060469687456 + 20060469687457.
It is an arithmetic number, because the mean of its divisors is an integer number (20060469687457).
Almost surely, 240120939374913 is an apocalyptic number.
It is an amenable number.
40120939374913 is a deficient number, since it is larger than the sum of its proper divisors (1).
40120939374913 is an equidigital number, since it uses as much as digits as its factorization.
40120939374913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4408992, while the sum is 55.
The spelling of 40120939374913 in words is "forty trillion, one hundred twenty billion, nine hundred thirty-nine million, three hundred seventy-four thousand, nine hundred thirteen".
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