Base | Representation |
---|---|
bin | 10010001111101011010101… |
… | …10001010100011000010011 |
3 | 12021001112112002212020110221 |
4 | 21013311222301110120103 |
5 | 20224320433142402423 |
6 | 221155211534333511 |
7 | 11310436533061336 |
oct | 1107655261243023 |
9 | 167045462766427 |
10 | 40121080825363 |
11 | 1186928919829a |
12 | 45bb89895a297 |
13 | 195052b67ac65 |
14 | 9c9c291ac61d |
15 | 498994a1be5d |
hex | 247d6ac54613 |
40121080825363 has 2 divisors, whose sum is σ = 40121080825364. Its totient is φ = 40121080825362.
The previous prime is 40121080825249. The next prime is 40121080825411. The reversal of 40121080825363 is 36352808012104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40121080825363 - 237 = 39983641871891 is a prime.
It is a super-2 number, since 2×401210808253632 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40121080820363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20060540412681 + 20060540412682.
It is an arithmetic number, because the mean of its divisors is an integer number (20060540412682).
Almost surely, 240121080825363 is an apocalyptic number.
40121080825363 is a deficient number, since it is larger than the sum of its proper divisors (1).
40121080825363 is an equidigital number, since it uses as much as digits as its factorization.
40121080825363 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 276480, while the sum is 43.
Adding to 40121080825363 its reverse (36352808012104), we get a palindrome (76473888837467).
The spelling of 40121080825363 in words is "forty trillion, one hundred twenty-one billion, eighty million, eight hundred twenty-five thousand, three hundred sixty-three".
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