4012113331 has 2 divisors, whose sum is σ = 4012113332. Its totient is φ = 4012113330.

The previous prime is 4012113317. The next prime is 4012113367. The reversal of 4012113331 is 1333112104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4012113331 - 2⁵ = 4012113299 is a prime.

It is a super-2 number, since 2×4012113331² = 32194106761575831122, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4012113299 and 4012113308.

It is not a weakly prime, because it can be changed into another prime (4012111331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006056665 + 2006056666.

It is an arithmetic number, because the mean of its divisors is an integer number (2006056666).

Almost surely, 2^4012113331 is an apocalyptic number.

4012113331 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012113331 is an equidigital number, since it uses as much as digits as its factorization.

4012113331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 4012113331 is about 63341.2451014345. The cubic root of 4012113331 is about 1589.0018300221.

Adding to 4012113331 its reverse (1333112104), we get a palindrome (5345225435).

The spelling of 4012113331 in words is "four billion, twelve million, one hundred thirteen thousand, three hundred thirty-one".