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4012123324193 is a prime number
BaseRepresentation
bin111010011000100101001…
…011110111111100100001
3112012112222202212101021022
4322120211023313330201
51011213312032333233
612311051034535225
7562603104364445
oct72304513677441
915175882771238
104012123324193
111307594025566
125496abb97515
1323145967c24a
14dc28b4a0825
156e57048b398
hex3a6252f7f21

4012123324193 has 2 divisors, whose sum is σ = 4012123324194. Its totient is φ = 4012123324192.

The previous prime is 4012123324151. The next prime is 4012123324211. The reversal of 4012123324193 is 3914233212104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2455887034129 + 1556236290064 = 1567127^2 + 1247492^2 .

It is a cyclic number.

It is not a de Polignac number, because 4012123324193 - 212 = 4012123320097 is a prime.

It is not a weakly prime, because it can be changed into another prime (4012123324393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006061662096 + 2006061662097.

It is an arithmetic number, because the mean of its divisors is an integer number (2006061662097).

Almost surely, 24012123324193 is an apocalyptic number.

It is an amenable number.

4012123324193 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012123324193 is an equidigital number, since it uses as much as digits as its factorization.

4012123324193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

Adding to 4012123324193 its reverse (3914233212104), we get a palindrome (7926356536297).

The spelling of 4012123324193 in words is "four trillion, twelve billion, one hundred twenty-three million, three hundred twenty-four thousand, one hundred ninety-three".