Base | Representation |
---|---|
bin | 1011101011010100101… |
… | …10000001101101011001 |
3 | 1102100121102220112201011 |
4 | 11311222112001231121 |
5 | 23033142311230333 |
6 | 504152141453521 |
7 | 40662336505234 |
oct | 5655226015531 |
9 | 1370542815634 |
10 | 401216117593 |
11 | 145178047565 |
12 | 659125712a1 |
13 | 2bab0586a55 |
14 | 155c18ca41b |
15 | a6835699cd |
hex | 5d6a581b59 |
401216117593 has 2 divisors, whose sum is σ = 401216117594. Its totient is φ = 401216117592.
The previous prime is 401216117509. The next prime is 401216117663. The reversal of 401216117593 is 395711612104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 210174568704 + 191041548889 = 458448^2 + 437083^2 .
It is a cyclic number.
It is not a de Polignac number, because 401216117593 - 237 = 263777164121 is a prime.
It is a super-2 number, since 2×4012161175932 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (401216115593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200608058796 + 200608058797.
It is an arithmetic number, because the mean of its divisors is an integer number (200608058797).
Almost surely, 2401216117593 is an apocalyptic number.
It is an amenable number.
401216117593 is a deficient number, since it is larger than the sum of its proper divisors (1).
401216117593 is an equidigital number, since it uses as much as digits as its factorization.
401216117593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45360, while the sum is 40.
Adding to 401216117593 its reverse (395711612104), we get a palindrome (796927729697).
The spelling of 401216117593 in words is "four hundred one billion, two hundred sixteen million, one hundred seventeen thousand, five hundred ninety-three".
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