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40121630551139 is a prime number
BaseRepresentation
bin10010001111101100010111…
…00010010110110001100011
312021001120221102021012110212
421013312023202112301203
520224323044410114024
6221155342253044335
711310456256501364
oct1107661342266143
9167046842235425
1040121630551139
1111869540528415
1245bba10a866ab
1319505b8523697
149c9c7c1c9b6b
154989c7e08a0e
hex247d8b896c63

40121630551139 has 2 divisors, whose sum is σ = 40121630551140. Its totient is φ = 40121630551138.

The previous prime is 40121630551133. The next prime is 40121630551183. The reversal of 40121630551139 is 93115503612104.

40121630551139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 40121630551139 - 240 = 39022118923363 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40121630551096 and 40121630551105.

It is not a weakly prime, because it can be changed into another prime (40121630551133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20060815275569 + 20060815275570.

It is an arithmetic number, because the mean of its divisors is an integer number (20060815275570).

Almost surely, 240121630551139 is an apocalyptic number.

40121630551139 is a deficient number, since it is larger than the sum of its proper divisors (1).

40121630551139 is an equidigital number, since it uses as much as digits as its factorization.

40121630551139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 41.

The spelling of 40121630551139 in words is "forty trillion, one hundred twenty-one billion, six hundred thirty million, five hundred fifty-one thousand, one hundred thirty-nine".