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40121635271513 is a prime number
BaseRepresentation
bin10010001111101100010111…
…10100010111001101011001
312021001120221202011000121112
421013312023310113031121
520224323102112142023
6221155342542150105
711310456344561405
oct1107661364271531
9167046852130545
1040121635271513
1111869543161954
1245bba12582335
1319505b94b70c3
149c9c7ca98105
154989c853c478
hex247d8bd17359

40121635271513 has 2 divisors, whose sum is σ = 40121635271514. Its totient is φ = 40121635271512.

The previous prime is 40121635271483. The next prime is 40121635271519. The reversal of 40121635271513 is 31517253612104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40082029495369 + 39605776144 = 6331037^2 + 199012^2 .

It is a cyclic number.

It is not a de Polignac number, because 40121635271513 - 28 = 40121635271257 is a prime.

It is not a weakly prime, because it can be changed into another prime (40121635271519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20060817635756 + 20060817635757.

It is an arithmetic number, because the mean of its divisors is an integer number (20060817635757).

Almost surely, 240121635271513 is an apocalyptic number.

It is an amenable number.

40121635271513 is a deficient number, since it is larger than the sum of its proper divisors (1).

40121635271513 is an equidigital number, since it uses as much as digits as its factorization.

40121635271513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 41.

Adding to 40121635271513 its reverse (31517253612104), we get a palindrome (71638888883617).

The spelling of 40121635271513 in words is "forty trillion, one hundred twenty-one billion, six hundred thirty-five million, two hundred seventy-one thousand, five hundred thirteen".