Base | Representation |
---|---|
bin | 10010001111101101000101… |
… | …00101011011101000000011 |
3 | 12021001121221100212200211111 |
4 | 21013312202211123220003 |
5 | 20224324342402432121 |
6 | 221155444505024151 |
7 | 11310501663315061 |
oct | 1107664245335003 |
9 | 167047840780744 |
10 | 40122017233411 |
11 | 11869719827543 |
12 | 45bbaba485057 |
13 | 195064a681269 |
14 | 9c9cb76c5031 |
15 | 4989ebd3b2e1 |
hex | 247da295ba03 |
40122017233411 has 2 divisors, whose sum is σ = 40122017233412. Its totient is φ = 40122017233410.
The previous prime is 40122017233387. The next prime is 40122017233433. The reversal of 40122017233411 is 11433271022104.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40122017233411 is a prime.
It is not a weakly prime, because it can be changed into another prime (40122017233211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20061008616705 + 20061008616706.
It is an arithmetic number, because the mean of its divisors is an integer number (20061008616706).
Almost surely, 240122017233411 is an apocalyptic number.
40122017233411 is a deficient number, since it is larger than the sum of its proper divisors (1).
40122017233411 is an equidigital number, since it uses as much as digits as its factorization.
40122017233411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 40122017233411 its reverse (11433271022104), we get a palindrome (51555288255515).
The spelling of 40122017233411 in words is "forty trillion, one hundred twenty-two billion, seventeen million, two hundred thirty-three thousand, four hundred eleven".
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