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401223331057 is a prime number
BaseRepresentation
bin1011101011010101100…
…01100010110011110001
31102100121221111000201111
411311222301202303301
523033201133043212
6504153000233321
740662455020603
oct5655261426361
91370557430644
10401223331057
111451811240aa
1265914a6b841
132bab1c11183
14155c2847173
15a683ee1ea7
hex5d6ac62cf1

401223331057 has 2 divisors, whose sum is σ = 401223331058. Its totient is φ = 401223331056.

The previous prime is 401223331013. The next prime is 401223331073. The reversal of 401223331057 is 750133322104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 270783896161 + 130439434896 = 520369^2 + 361164^2 .

It is a cyclic number.

It is not a de Polignac number, because 401223331057 - 27 = 401223330929 is a prime.

It is a super-2 number, since 2×4012233310572 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (401223332057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200611665528 + 200611665529.

It is an arithmetic number, because the mean of its divisors is an integer number (200611665529).

Almost surely, 2401223331057 is an apocalyptic number.

It is an amenable number.

401223331057 is a deficient number, since it is larger than the sum of its proper divisors (1).

401223331057 is an equidigital number, since it uses as much as digits as its factorization.

401223331057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 31.

The spelling of 401223331057 in words is "four hundred one billion, two hundred twenty-three million, three hundred thirty-one thousand, fifty-seven".