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40122500953 is a prime number
BaseRepresentation
bin100101010111011111…
…001100011101011001
310211120012120020012211
4211113133030131121
51124132330012303
630233152235121
72620162426303
oct452737143531
9124505506184
1040122500953
111601a1188a7
127938b3baa1
133a25573932
141d28978973
15109c63366d
hex9577cc759

40122500953 has 2 divisors, whose sum is σ = 40122500954. Its totient is φ = 40122500952.

The previous prime is 40122500897. The next prime is 40122500959. The reversal of 40122500953 is 35900522104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34111134864 + 6011366089 = 184692^2 + 77533^2 .

It is a cyclic number.

It is not a de Polignac number, because 40122500953 - 29 = 40122500441 is a prime.

It is not a weakly prime, because it can be changed into another prime (40122500959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20061250476 + 20061250477.

It is an arithmetic number, because the mean of its divisors is an integer number (20061250477).

Almost surely, 240122500953 is an apocalyptic number.

It is an amenable number.

40122500953 is a deficient number, since it is larger than the sum of its proper divisors (1).

40122500953 is an equidigital number, since it uses as much as digits as its factorization.

40122500953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 40122500953 in words is "forty billion, one hundred twenty-two million, five hundred thousand, nine hundred fifty-three".