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40123615513 is a prime number
BaseRepresentation
bin100101010111100011…
…011100100100011001
310211120021122212002211
4211113203130210121
51124133121144023
630233232155121
72620205050612
oct452743344431
9124507585084
1040123615513
111601a80a223
127939398aa1
133a25874037
141d28b88c09
15109c7a3a0d
hex9578dc919

40123615513 has 2 divisors, whose sum is σ = 40123615514. Its totient is φ = 40123615512.

The previous prime is 40123615501. The next prime is 40123615523. The reversal of 40123615513 is 31551632104.

40123615513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38652739609 + 1470875904 = 196603^2 + 38352^2 .

It is a cyclic number.

It is not a de Polignac number, because 40123615513 - 221 = 40121518361 is a prime.

It is not a weakly prime, because it can be changed into another prime (40123615523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20061807756 + 20061807757.

It is an arithmetic number, because the mean of its divisors is an integer number (20061807757).

Almost surely, 240123615513 is an apocalyptic number.

It is an amenable number.

40123615513 is a deficient number, since it is larger than the sum of its proper divisors (1).

40123615513 is an equidigital number, since it uses as much as digits as its factorization.

40123615513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 40123615513 in words is "forty billion, one hundred twenty-three million, six hundred fifteen thousand, five hundred thirteen".