401240324131 has 4 divisors (see below), whose sum is σ = 409777352352. Its totient is φ = 392703295912.

The previous prime is 401240324099. The next prime is 401240324189. The reversal of 401240324131 is 131423042104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 401240324131 - 2⁵ = 401240324099 is a prime.

It is a super-2 number, since 2×401240324131² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 401240324096 and 401240324105.

It is not an unprimeable number, because it can be changed into a prime (401240324231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4268514040 + ... + 4268514133.

It is an arithmetic number, because the mean of its divisors is an integer number (102444338088).

Almost surely, 2^401240324131 is an apocalyptic number.

401240324131 is a deficient number, since it is larger than the sum of its proper divisors (8537028221).

401240324131 is an equidigital number, since it uses as much as digits as its factorization.

401240324131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8537028220.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 401240324131 its reverse (131423042104), we get a palindrome (532663366235).

The spelling of 401240324131 in words is "four hundred one billion, two hundred forty million, three hundred twenty-four thousand, one hundred thirty-one".