Base | Representation |
---|---|
bin | 101101100111011010100011… |
… | …0100110110010100011000101 |
3 | 1221121200021222202222212022111 |
4 | 1123032311012212302203011 |
5 | 410042414213012131003 |
6 | 3541211415243301021 |
7 | 150341505030444145 |
oct | 13316650646624305 |
9 | 1847607882885274 |
10 | 401241324333253 |
11 | 106936543278a18 |
12 | 3900330b81a771 |
13 | 142b6b82392851 |
14 | 7112280196925 |
15 | 315c31abeae6d |
hex | 16ced469b28c5 |
401241324333253 has 16 divisors (see below), whose sum is σ = 427596509306880. Its totient is φ = 375628696199856.
The previous prime is 401241324333203. The next prime is 401241324333259. The reversal of 401241324333253 is 352333423142104.
It is not a de Polignac number, because 401241324333253 - 221 = 401241322236101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (401241324333259) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 352862068 + ... + 353997346.
It is an arithmetic number, because the mean of its divisors is an integer number (26724781831680).
Almost surely, 2401241324333253 is an apocalyptic number.
It is an amenable number.
401241324333253 is a deficient number, since it is larger than the sum of its proper divisors (26355184973627).
401241324333253 is a wasteful number, since it uses less digits than its factorization.
401241324333253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1462296.
The product of its (nonzero) digits is 622080, while the sum is 40.
Adding to 401241324333253 its reverse (352333423142104), we get a palindrome (753574747475357).
The spelling of 401241324333253 in words is "four hundred one trillion, two hundred forty-one billion, three hundred twenty-four million, three hundred thirty-three thousand, two hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •