Base | Representation |
---|---|
bin | 111010011000110111000… |
… | …110111001101011000001 |
3 | 112012120202201122211020201 |
4 | 322120313012321223001 |
5 | 1011214421021313213 |
6 | 12311140535405201 |
7 | 562613415232636 |
oct | 72306706715301 |
9 | 15176681584221 |
10 | 4012424010433 |
11 | 1307728828593 |
12 | 549774823801 |
13 | 2314a6a5a4b7 |
14 | dc2b93b218d |
15 | 6e58ba836dd |
hex | 3a6371b9ac1 |
4012424010433 has 2 divisors, whose sum is σ = 4012424010434. Its totient is φ = 4012424010432.
The previous prime is 4012424010409. The next prime is 4012424010449. The reversal of 4012424010433 is 3340104242104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3454066854144 + 558357156289 = 1858512^2 + 747233^2 .
It is a cyclic number.
It is not a de Polignac number, because 4012424010433 - 29 = 4012424009921 is a prime.
It is not a weakly prime, because it can be changed into another prime (4012424010493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006212005216 + 2006212005217.
It is an arithmetic number, because the mean of its divisors is an integer number (2006212005217).
Almost surely, 24012424010433 is an apocalyptic number.
It is an amenable number.
4012424010433 is a deficient number, since it is larger than the sum of its proper divisors (1).
4012424010433 is an equidigital number, since it uses as much as digits as its factorization.
4012424010433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 4012424010433 its reverse (3340104242104), we get a palindrome (7352528252537).
The spelling of 4012424010433 in words is "four trillion, twelve billion, four hundred twenty-four million, ten thousand, four hundred thirty-three".
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