Base | Representation |
---|---|
bin | 101101100111011011110011… |
… | …0111011110111011110010111 |
3 | 1221121200112221020110220122212 |
4 | 1123032313212323313132113 |
5 | 410042440220114304030 |
6 | 3541212542212544035 |
7 | 150341631502160201 |
oct | 13316674673673627 |
9 | 1847615836426585 |
10 | 401244014213015 |
11 | 1069376a3682446 |
12 | 3900394062201b |
13 | 142b71c0744a8c |
14 | 7112457513771 |
15 | 315c426e32595 |
hex | 16cede6ef7797 |
401244014213015 has 32 divisors (see below), whose sum is σ = 510054782976000. Its totient is φ = 302379961618944.
The previous prime is 401244014212991. The next prime is 401244014213033. The reversal of 401244014213015 is 510312410442104.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-401244014213015 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24002111 + ... + 37129359.
It is an arithmetic number, because the mean of its divisors is an integer number (15939211968000).
Almost surely, 2401244014213015 is an apocalyptic number.
401244014213015 is a deficient number, since it is larger than the sum of its proper divisors (108810768762985).
401244014213015 is a wasteful number, since it uses less digits than its factorization.
401244014213015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13131311.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 401244014213015 its reverse (510312410442104), we get a palindrome (911556424655119).
The spelling of 401244014213015 in words is "four hundred one trillion, two hundred forty-four billion, fourteen million, two hundred thirteen thousand, fifteen".
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