40126413262113 has 24 divisors (see below), whose sum is σ = 60494307368040. Its totient is φ = 25606056003840.

The previous prime is 40126413262037. The next prime is 40126413262183. The reversal of 40126413262113 is 31126231462104.

40126413262113 is a `hidden beast` number, since 4 + 0 + 1 + 2 + 6 + 4 + 13 + 2 + 621 + 13 = 666.

40126413262113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 11176665295104 + 28949747967009 = 3343152^2 + 5380497^2 .

It is not a de Polignac number, because 40126413262113 - 2¹⁰ = 40126413261089 is a prime.

It is a super-2 number, since 2×40126413262113² (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (40126413262183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1025864098 + ... + 1025903211.

It is an arithmetic number, because the mean of its divisors is an integer number (2520596140335).

Almost surely, 2^{40126413262113} is an apocalyptic number.

It is an amenable number.

40126413262113 is a deficient number, since it is larger than the sum of its proper divisors (20367894105927).

40126413262113 is a wasteful number, since it uses less digits than its factorization.

40126413262113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2051767409 (or 2051767406 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 36.

The spelling of 40126413262113 in words is "forty trillion, one hundred twenty-six billion, four hundred thirteen million, two hundred sixty-two thousand, one hundred thirteen".