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4012855404499 is a prime number
BaseRepresentation
bin111010011001010000110…
…100100010011111010011
3112012121212210101220122201
4322121100310202133103
51011221311440420444
612311251425544031
7562630204100404
oct72312064423723
915177783356581
104012855404499
11130792a296307
125498751a5017
13231545241466
14dc31a7c99ab
156e5b4898dd4
hex3a650d227d3

4012855404499 has 2 divisors, whose sum is σ = 4012855404500. Its totient is φ = 4012855404498.

The previous prime is 4012855404469. The next prime is 4012855404511. The reversal of 4012855404499 is 9944045582104.

4012855404499 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4012855404499 - 225 = 4012821850067 is a prime.

It is a super-2 number, since 2×40128554044992 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4012855404469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006427702249 + 2006427702250.

It is an arithmetic number, because the mean of its divisors is an integer number (2006427702250).

Almost surely, 24012855404499 is an apocalyptic number.

4012855404499 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012855404499 is an equidigital number, since it uses as much as digits as its factorization.

4012855404499 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8294400, while the sum is 55.

The spelling of 4012855404499 in words is "four trillion, twelve billion, eight hundred fifty-five million, four hundred four thousand, four hundred ninety-nine".