Base | Representation |
---|---|
bin | 111010011001011001100… |
… | …000011101000000101100 |
3 | 112012122020221121202010020 |
4 | 322121121200131000230 |
5 | 1011222111242242444 |
6 | 12311314113242140 |
7 | 562633623553203 |
oct | 72313140350054 |
9 | 15178227552106 |
10 | 4013001134124 |
11 | 13079a4581114 |
12 | 5498b5b63350 |
13 | 2315694a66c8 |
14 | dc331cc223a |
15 | 6e5c2583119 |
hex | 3a65981d02c |
4013001134124 has 24 divisors (see below), whose sum is σ = 9394169873088. Its totient is φ = 1333309821840.
The previous prime is 4013001134123. The next prime is 4013001134141. The reversal of 4013001134124 is 4214311003104.
It is a super-2 number, since 2×40130011341242 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4013001134094 and 4013001134103.
It is not an unprimeable number, because it can be changed into a prime (4013001134123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 544649022 + ... + 544656389.
It is an arithmetic number, because the mean of its divisors is an integer number (391423744712).
Almost surely, 24013001134124 is an apocalyptic number.
It is an amenable number.
4013001134124 is an abundant number, since it is smaller than the sum of its proper divisors (5381168738964).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4013001134124 is a wasteful number, since it uses less digits than its factorization.
4013001134124 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1089305725 (or 1089305723 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 4013001134124 its reverse (4214311003104), we get a palindrome (8227312137228).
The spelling of 4013001134124 in words is "four trillion, thirteen billion, one million, one hundred thirty-four thousand, one hundred twenty-four".
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