Base | Representation |
---|---|
bin | 100101010111111011… |
… | …111011001100111001 |
3 | 10211120201201212110211 |
4 | 211113323323030321 |
5 | 1124141242014231 |
6 | 30234021511121 |
7 | 2620313435062 |
oct | 452773731471 |
9 | 124521655424 |
10 | 40130032441 |
11 | 160233a2374 |
12 | 793b5724a1 |
13 | 3a26caca35 |
14 | 1d29979569 |
15 | 109d11eeb1 |
hex | 957efb339 |
40130032441 has 2 divisors, whose sum is σ = 40130032442. Its totient is φ = 40130032440.
The previous prime is 40130032421. The next prime is 40130032451. The reversal of 40130032441 is 14423003104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37867603216 + 2262429225 = 194596^2 + 47565^2 .
It is a cyclic number.
It is not a de Polignac number, because 40130032441 - 217 = 40129901369 is a prime.
It is a super-2 number, since 2×401300324412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40130032421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065016220 + 20065016221.
It is an arithmetic number, because the mean of its divisors is an integer number (20065016221).
Almost surely, 240130032441 is an apocalyptic number.
It is an amenable number.
40130032441 is a deficient number, since it is larger than the sum of its proper divisors (1).
40130032441 is an equidigital number, since it uses as much as digits as its factorization.
40130032441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 40130032441 its reverse (14423003104), we get a palindrome (54553035545).
The spelling of 40130032441 in words is "forty billion, one hundred thirty million, thirty-two thousand, four hundred forty-one".
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