4013005393 has 2 divisors, whose sum is σ = 4013005394. Its totient is φ = 4013005392.

The previous prime is 4013005387. The next prime is 4013005433. The reversal of 4013005393 is 3935003104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3988175104 + 24830289 = 63152^2 + 4983^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013005393 - 2²¹ = 4010908241 is a prime.

It is a super-2 number, since 2×4013005393² = 32208424568494168898, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4013005343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006502696 + 2006502697.

It is an arithmetic number, because the mean of its divisors is an integer number (2006502697).

Almost surely, 2^4013005393 is an apocalyptic number.

It is an amenable number.

4013005393 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013005393 is an equidigital number, since it uses as much as digits as its factorization.

4013005393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4860, while the sum is 28.

The square root of 4013005393 is about 63348.2864251276. The cubic root of 4013005393 is about 1589.1195886688.

Adding to 4013005393 its reverse (3935003104), we get a palindrome (7948008497).

The spelling of 4013005393 in words is "four billion, thirteen million, five thousand, three hundred ninety-three".