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40131025001 is a prime number
BaseRepresentation
bin100101010111111111…
…101101100001101001
310211120210121022000022
4211113333231201221
51124142020300001
630234055050225
72620325040614
oct452777554151
9124523538008
1040131025001
1116023a10071
12793b970975
133a27269752
141d29b5717b
15109d26911b
hex957fed869

40131025001 has 2 divisors, whose sum is σ = 40131025002. Its totient is φ = 40131025000.

The previous prime is 40131024943. The next prime is 40131025007. The reversal of 40131025001 is 10052013104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36804504025 + 3326520976 = 191845^2 + 57676^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40131025001 is a prime.

It is a super-2 number, since 2×401310250012 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40131025007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065512500 + 20065512501.

It is an arithmetic number, because the mean of its divisors is an integer number (20065512501).

Almost surely, 240131025001 is an apocalyptic number.

It is an amenable number.

40131025001 is a deficient number, since it is larger than the sum of its proper divisors (1).

40131025001 is an equidigital number, since it uses as much as digits as its factorization.

40131025001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

Adding to 40131025001 its reverse (10052013104), we get a palindrome (50183038105).

The spelling of 40131025001 in words is "forty billion, one hundred thirty-one million, twenty-five thousand, one".